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The value of K for (k+1)x^2-2(k-1)x+1 = 0 has real and equal roots.
cos(x)y''+sin(x)y=2cos^3(x)sin(x)-1
Consider R be a relation from A to B, that is, take R A Χ B. Then Domain R = {a: a € A, (a, b) € R for any b € B} i.e. domain of R is the set of all the first components of
3456+3694
2x^3+5x^2+2x+5
A circular disc of 6 cm radius is divided into three sectors with central angles 1200, 1500,900. What part of the circle is the sector with central angles 1200. Also give the ratio
what is answer ? + 5=10+5
13 1/4 34 56/89
There are really three various methods for doing such integral. Method 1: This method uses a trig formula as, ∫sin(x) cos(x) dx = ½ ∫sin(2x) dx = -(1/4) cos(2x) + c
Find the normalized differential equation which has { x, xe^x } as its fundamental set
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