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State and prove Demorgan's second theorem Proof: Demorgan's second theorem
= A‾ + B‾
The two sides of the equation here = A‾ + B‾ is represented through the logic diagrams demonstarted in fig.(c) and (d).
The equality of the logic diagrams of fig.(c) and (d) is proved through the truth table illustrated in table
Inputs
Intermediate Values
Outputs
A
B
A .B
A‾
B‾
A‾ + B‾
0
1
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