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How many integers satisfy (sqrt n- sqrt 8836)^2<1? Solution) sqrt 8836 = 94 , let sqrt n=xthe equation becomes...(x-94)^2 < 1(x-94)^2 - 1 < 0(x-95)(x-93) < 0hence 938649 < n < 9025 the number of integers are 9024-8650+1=375
Hence the number of Integers are 375 (ANS).
Properties of Logarithms 1. log a xy = log a x + log a y 2. = log a x - log a y 3. log a x n = n log
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