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How many integers satisfy (sqrt n- sqrt 8836)^2<1? Solution) sqrt 8836 = 94 , let sqrt n=xthe equation becomes...(x-94)^2 < 1(x-94)^2 - 1 < 0(x-95)(x-93) < 0hence 938649 < n < 9025 the number of integers are 9024-8650+1=375
Hence the number of Integers are 375 (ANS).
if area of a rectangle is 27 sqmtr and it perimeter is 24 m find the length and breath#
project on shares and dividends
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1. Consider the following context free grammar G with start symbol S (we write E for the empty string, epsilon): S ---> bB | aSS A ---> aB | bAA B ---> E | bA | aS a. D
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Left-handed limit We say provided we can make f(x) as close to L as we desire for all x sufficiently close to a and x Note that the change in notation is extremely m
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