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How many integers satisfy (sqrt n- sqrt 8836)^2<1? Solution) sqrt 8836 = 94 , let sqrt n=xthe equation becomes...(x-94)^2 < 1(x-94)^2 - 1 < 0(x-95)(x-93) < 0hence 938649 < n < 9025 the number of integers are 9024-8650+1=375
Hence the number of Integers are 375 (ANS).
what iz the value of x if y=56
Coastal Cable had 1,440,000 customers within January of 2002. During the first half of 2002 the company launched a large advertising campaign. Through the end of 2002 they had 1,80
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A series is said to be in Arithmetic Progression (A.P.) if the consecutive numbers in the series differs by a constant value. This constant value is referre
Solve : 4x2+2x+3=0 Ans) x^2 + (1/2)x = -(3/4) (x+1/4)^2 = 1/16 - 3/4 = -11/16 implies x = (-1+i(11)^(1/2))/4 and its conjugate.
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