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A,B,C are natural numbers and are in arithmetic progressions and a+b+c=21.then find the possible values for a,b,cSolution) a+b+c=21a+c=2b3b=21b=7a can be 1,2,3,4,5,6c can be 13,12,11,10,9,8
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Here we look at only the rules without going into their proofs. They are: a 0. If a If a If a
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