Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
a)Solve for ?, if tan5? = 1.
Ans: Tan 5? = 1 ⇒ ? =45/5 ⇒ ?=9o.
b)Solve for ? if Sin?/1 + Cos? + 1 + Cos?/ Sin? = 4 .
Ans: Sin?/1 + Cos? + 1 + Cos?/ Sin? = 4
Sin2?/1 + 1 (Cos?)2/ Sin?(1 + Cos?) = 4
Sin2?+1 + Cos2? + 2cos?/ Sin? +Sin?Cos? = 4
2 +2Cos? / Sin?(1+ cos?) =4
2+(1+ cos?)/Sin?(1+ cos?) = 4
2/sin? = 4
sin ? = 1/2
sin ? = sin 30
? = 30o
how do you determine and classify all the critical points of a function
Which of the subsequent numbers will yield a number larger than 23.4 while it is multiplied by 23.4? When multiplying through a number less than 1, you get a product in which i
A series is said to be in Arithmetic Progression (A.P.) if the consecutive numbers in the series differs by a constant value. This constant value is referre
Simplify following. Suppose that x, y, & z are positive. √ y 7 Solution In this case the exponent (7) is larger than the index (2) and thus the fir
how do you multiply fractions
Graphical Understanding of Derivatives: A ladder 26 feet long is leaning against a wall. The ladder begins to move such that the bottom end moves away from the wall at a const
find h in the parallelogram
Q. Finding the Area of a Triangle? There are three commonly used methods to find the area of a triangle. The method you use to find the area depends on the information you kno
3x+y=9 5x-y=7
Prove that a simple graph is connected if and only if it has a spanning tree. Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd