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These are the only possibilities for solving quadratic equations in standard form. However Note that if we begin with rational expression in the equation we might get different so
-3/4(x=6/5)>-159/160
x= sum of 2 perfect cubes in two ways
(2x^2+16x+24)/(3x^2) /(x+6)
2x^2+7x+3/x^2-2x-15
how do I do complex fractions X over 25 over x over 15
2x-3y=2 5x+4y=28
is force applied to the brakes on a car, and stopping distance a direct variation?
6[5b+9]=2b+9.
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