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X6-81X2=0 what is the real solution
how do you do this im failing mmath
2. ABCD was a square sheet of paper, 6 cm on a side. As shown, corner D was folded to point F on the diagonal BD. The area of triangle EFG equals the area of the shaded L-shaped po
Y=5/4x-1/2
2(5+6csquared)-30divided by 3 c=2 d=4
The last set of transformations which we're going to be looking at in this section isn't shifts, but in spite of they are called reflections & there are two of them. Reflection
Find the standard form equation for... 4x^2-y^2+24x+4y+28=0
Sketch the graph of P ( x ) = 5x 5 - 20x 4 + 5x 3 + 50x2 - 20x - 40 . Solution We set up the zeroes & multiplicities of this polynomial in the previous section hence
4(x)^2-40x+107 in standard form
How do i do an fx problem?
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