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SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in a memory location or a register, by the specified count in the instruction and inserts zeros in the shifted positions. The result is in the destination operand. Given figure describe execution of this instruction. This instruction shifts operand through the carry flag.
Figure: Execution SHR Instruction
SAR : Shift Arithmetic Right: This instruction performs right shifts on the operand byte or word that might be memory location or register by the particular count in the instruction and inserts the most significant bit of the operand in the new inserted positions. The result is in the destination operand. Given figure described execution of the instruction. All of the condition code flags are affected from this. This shift operation shifts the operand through the carry flag.
Figure : Execution of SAR Instruction
Machine Level Programs In this section, a few machine levels programming instance, rather then, instruction sequences are presented for comparing the 8086 programming with that
write and run a programme using 8086 assembly language that interchange the lower four bits of AL registered with upper four bits.
2. Write a program to separate out positive and negative numbers from a given series of 16-bit hexadecimal numbers.
a- Trace the following program fragment and find out the content of ax after the the execution of the program. X db 5,7 -3,-9,4,-7,9 Mov
A/D conversion: Basic tasks: (a) Write a program that will read and display the analog voltage on pin PE7 approximately once every second. (b) Write a program that will read and d
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H
LENGTH : Byte Length of a Label: This directive is not available in MASM. This is used to mention to the length of a data array or a string. MOV CX. LENGTH ARRAY This sta
END : END of Program:- The END directive marks the ending of the assembly language program. When the assembler comes across this END directive, it avoided the source lines avai
I need a division subroutine. Asks for two inputs, then displays the inputs and shows the answer with a remainder. Mine isnt displaying the inputs correctly.
I am assigned to implement dijkstra algorithm in assembly language. I am not a novice in assembly. I need help implementing it.Kindly if anyone then please.
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