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If A, B and P are the points (-4, 3), (0, -2) and (α,β) respectively and P is equidistant from A and B, show that 8α - 10β + 21= 0.
Ans : AP = PB ⇒ AP2 = PB2
(∝ + 4)2 + (β - 3)2 = ∝2 +(β + 2)2
∝2 + 8∝ + 16 + β2 - 6β + 9 = ∝2 + β2 + 4β + 4
8∝ - 6β - 4β + 25 - 4 = 0
8∝ - 10β + 21 = 0
Equivalent or Equal sets Two sets C and D are said to be equal whether every member of set C belongs to D and every member of set D belongs also to C.
A,B,C are natural numbers and are in arithmetic progressions and a+b+c=21.then find the possible values for a,b,c Solution) a+b+c=21 a+c=2b 3b=21 b=7 a can be 1,2,3,4,5,6 c c
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