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Q. Show Crystal Field Splitting in Square Planar Complexes?
In a d1 or d2 system the electrons will always go in the 'e' set of orbitals with the release of corresponding amount of energy (CFSE). For d1 it will be -3/5Δt and for d2 it will be 2(-3/5Δt) or -6/5Δt. These values can be converted in terms of & for comparison. Again for systems from d3 to d6 there are two different configurations possible in each case as shown in Fig.
From Table 14.5, you can see that the pairing energies (P) andΔ0 for common ligands are of comparable order of magnitude. It is also true that Δt is almost one-half the value of Δ0. Hence we can say that pairing energy, P, is almost double the value of at or in other words P >>Δ0. Under the circumstances all the electrons in any system in tetrahedral field will- spread out in e and t sets of orbitals rather than pair up in e-orbitals. To put it in other terms it is said that the low spin tetrahedral, complexes of the first row transition elements are not known.
Crystal Field Splitting in Square Planar Complexes
How do I find the Noble Gas Configuration?
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