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Service standards:
The forum of regulators (constituted through the central government for consistency in regulation in the area of distribution) will decide the basic framework of service standards so in which the standards regarding quality, continuity and reliability of service could be enforced. Licensees failing to meet this standard will face penalties.
Agricultural users:
The tariffs for agricultural use are to be fixed so as to address concerns about sustainable utilization of ground water resources. The provision of free electricity is not desirable as it encourages wasteful consumption of electricity and in most of the cases, depletion of the water table. For promote energy efficiency, time-differentiated tariffs are to be put in place within one year for huge consumers of 1 MW and above.
i dont understand why equalizer connection is not used in wave windings?
Q. What are the benefits of ccs over in-channel signalling? The benefits of CCS over in-channel signalling are listed below: a. Information can be exchange between processor
For a 45-kVA, three-phase, wye-connected, 220- V synchronous machine at rated armature current, the short-circuit load loss (total for three phases) is 1.80 kWat a temperature of 2
Reproducibility and repeatability are measures of closeness with which a given input may be measured over again. The two terms cause confusion. Therefore, a distinction is made bet
Define Salient-pole Rotor Construction - Synchronous Machines? Salient-pole rotor construction on the other hand, may be used for low to medium speed applications. The machines
D flipflop
Technical Losses in Power Systems The technical losses in power systems occur because of energy dissipated in the conductors and equipment used for transmission, transformat
Define Serial In - Parallel Out Shift Registers? For this type of register data bits are entered serially in the same manner as discussed in the last section and the difference
2365 302 written exam
Q. In a differentiating circuit, R=10 kW,and C=2.2μF.If the input voltage goes from 0V to 10 V at a constant rate in 0.4s, determine the output voltage. Solution: e 0 =
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