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Semidifference via NOT IN and a subquery
SELECT StudentId
FROM IS_CALLED
WHERE Name = 'Devinder'
AND StudentId NOT IN (SELECT StudentId
FROM IS_ENROLLED_ON
WHERE CourseId = 'C1')
In above Example < > ALL replaces NOT IN and in the absence of NULL has the same effect. It reads, somewhat ambiguously, as "not equal to all". In fact the expression yields TRUE if and only if the condition comparing StudentId values is TRUE for every row in the result of the subquery.
Using a join on 3 tables, select 5 columns and 10 rows from the 3 tables without the use of a Cartesian product Query: SELECT E.LAST_NAME, E.FIRST_NAME, S.BUILDING, S.BRAN
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