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How can you rotate a Binary Tree? Explain right and left rotations by taking an example.
If after we have inserted a node in a Binary search tree, the balancing factor (height of left subtree - height of right subtree) of each node remains 0, 1 and -1 then there is no need of modification or alteration of original tree. If balancing factor of any node is either +2 or -2, the tree becomes unbalanced. It can be balanced by using left rotation or right rotation or a combination of both the rotations.
For example
1. In the tree drawn below, after inserting node 70 , the balance factor of tree at the root node (2) so the tree is rotated left to have a height balanced tree shown by (a) to (b):
2. In the tree drawn below, after inserting 10 the balance factor of tree at root node is +2 so the tree is rotated right to have height balanced tree as shown by(a) to (b) below:
The smallest element of an array's index is called its Lower bound.
explain two strategies to implement state charts with the help of an example of each.
Objectives The purpose of this project is to give you significant exposure to Binary Search Trees (BST), tree traversals, and recursive code. Background An arbitrary BST i
What are circular queues? Circular queue: Static queues have a very large drawback that once the queue is FULL, even though we erase few elements from the "front" and relieve
Q. Write down an algorithm to add an element in the end of the circular linked list. A n s . Algo rithm to Add the Element at the End of Circular Linked Lists
Write an algorithm by using pseudocode which: Inputs top speeds of 5000 cars Outputs fastest speed and the slowest speed Outputs average speed of all the 5000 cars
Which sorting methods would be most suitable for sorting a list which is almost sorted Bubble Sorting method.
A B-tree of minimum degree t can maximum pointers in a node T pointers in a node.
Let us assume a file of 5 records that means n = 5 And k is a sorted array of keys of those 5 records. Let key = 55, low = 0, high = 4 Iteration 1: mid = (0+4)/2 = 2
Q. Reverse the order of the elements on a stack S (i) by using two additional stacks (ii) by using one additional queue. Ans : L e t S be the stac
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