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How can you rotate a Binary Tree? Explain right and left rotations by taking an example.
If after we have inserted a node in a Binary search tree, the balancing factor (height of left subtree - height of right subtree) of each node remains 0, 1 and -1 then there is no need of modification or alteration of original tree. If balancing factor of any node is either +2 or -2, the tree becomes unbalanced. It can be balanced by using left rotation or right rotation or a combination of both the rotations.
For example
1. In the tree drawn below, after inserting node 70 , the balance factor of tree at the root node (2) so the tree is rotated left to have a height balanced tree shown by (a) to (b):
2. In the tree drawn below, after inserting 10 the balance factor of tree at root node is +2 so the tree is rotated right to have height balanced tree as shown by(a) to (b) below:
In a chained hash table, each table entry is a pointer to a collection of elements. It can be any collection that supports insert, remove, and find, but is commonly a linked list.
Q. Enumerate number of operations possible on ordered lists and arrays. Write procedures to insert and delete an element in to array.
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N = number of rows of the graph D[i[j] = C[i][j] For k from 1 to n Do for i = 1 to n Do for j = 1 to n D[i[j]= minimum( d ij (k-1) ,d ik (k-1) +d kj (k-1)
The below figure illustrates the BOM (Bill of Materials) for product A. The MPS (Material requirements Planning) start row in the master production schedule for product A calls for
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