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Role in Education and Training:-A multimedia presentation is an important way to introduce new concepts or described a new technology. Individuals determine it easy to understand & use.
Multimedia can be utilized for education, training, digital publications, simulations, museum exhibits and so much more. Along with the advent of multimedia authoring applications such as Flash, Shockwave and Director amongst a host of other equally increasing applications are obtainable in the market today. Your application of multimedia is only restricted by your imagination. In technologies Training or instructional methods and advancement have always gone hand in hand. For example as:
Sound Editing Programs; Sound editing tools for both digitized and MIDI sound; by that you see music and also hear it. Through drawing a representation of a sound in fine growths,
what is frame buffer
Assumption regarding to the Digital Differential Analyzer Algorithm The line generation by DDA is discussed merely for the first Quadrant, whether the line lies in the other q
why there is coating of phosphorous on CRT screen?
AsHow has internet-based streaming technology changed the way people consume television and digital entertainment?k question #Minimum 100 words accepted#
Proof of subsequent properties of Bezier curves Note: Proof of subsequent properties of Bezier curves is left as a work out for the students P' (0) = n (p 1 - p 0 ) P
What happens while two polygons have similar z value and the z-buffer algorithm is utilized? Solution : z-buffer algorithms, varies colors at a pixel if z(x,y)
Two Modes of Operation of Tablets Tablets typically sustain two modes of operation as: 1) Digitizer Mode: creates a one-for-one connection between screen and tablet.
Given two triangles P along with vertices as P1(100,100,50), P2(50,50,50), P3(150,50,50) and q along with vertices as Q1(40,80,60), q2(70,70,50), Q3( 10,75,70), determine that tria
Algorithm (scan-line): For each scan line perform from step (1) to (3). 1) For all pixels on a scan-line, arrange depth [x]=1.0 i.e. max value and Intensity [x] = background
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