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At a distance of 4,000 ft from the launch site, a spectator is observing a rocket being launched. If the rocket lifts off vertically and is rising at a speed of 600 ft/sec when it is at an altitude of 3,000 ft, how fast is the distance between the rocket and the spectator changing at that instant?Solution) Distance=s=√(40002+h2), rate of change of distance=ds/dt=(ds/dh)(dh/dt)=(d(√(40002+h2)/dh)(dh/dt),dh/dt=600 ft/sec
What is proton-neutron hypothesis? Explain it?
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state and explain pauli''s exclusion principle
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The minimum real charge on any particle which can exist is: (1)1.6x 10 -19 coulomb (2) 1.6x 10 -10 coulomb (3)4.8 x 10 -10 coulomb (4)Zero Ans: (1)1.6x 10 -19 c
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