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Return by reference:
The return value of the function must be an address variable. In following program the
function returns the value of x or y and their types are declared as reference variable.
int &f_ref(int &c, int &d); // int &f_ref(int, int) is invalid for reference variable void main( )
{int a, b,c;
c=f_ref(a, b);
}
int &f_ref(int &x, int &y)
{if x>y return x; else return y;
how can i easily make a program?
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Pointer to function: int mul(int a, int b, int c) { return a*b*c; } void main() { int (*function_pointer)(int, int, int); function_pointer = &mul;
program
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