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Return by reference:
The return value of the function must be an address variable. In following program the
function returns the value of x or y and their types are declared as reference variable.
int &f_ref(int &c, int &d); // int &f_ref(int, int) is invalid for reference variable void main( )
{int a, b,c;
c=f_ref(a, b);
}
int &f_ref(int &x, int &y)
{if x>y return x; else return y;
A: Multiple providers of libraries might employ common global identifiers causing a name collision whereas an application attempt to link with two or more such libraries. The names
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
A: A reference has to always refer to some object and, so, must always be initialized; pointers do not have such limits. A pointer may be reassigned to point to distinct objects wh
C Program for REMOVING CHAR WHICH U WANT void main() { int i,j; char a[100],r; clrscr(); for(i=0;i
Multidimensional Arrays - Every dimension is specified in separate brackets e.g. int arr[4][3]; This is a two-dimensional array with 4 as row dimension and 3 as
a program to find the area under curve y=f(x) between x=a and x=b,integrate y=f(x) between the limits of a and b.
A: no, can't. The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a
Addition of array elements: #define rows 3 #define cols 3 void main() { int i=0,j=0,sum=0; int arr[rows][cols];
What if one forget the [] when deleteing array allocated through new T[n]? A: All life comes to a disastrous end. It is the programmer's responsibility not the compiler's to
compute algorithm to calculate simple interest
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