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Return by reference:
The return value of the function must be an address variable. In following program the
function returns the value of x or y and their types are declared as reference variable.
int &f_ref(int &c, int &d); // int &f_ref(int, int) is invalid for reference variable void main( )
{int a, b,c;
c=f_ref(a, b);
}
int &f_ref(int &x, int &y)
{if x>y return x; else return y;
How can I handle a constructor that fails?
Program is to display the contents of file on a screen: Write a program to display the contents of file on a screen void main() { clrscr(); ifstream fin("ascii
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Write C++ code for calculating the time table
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