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A ball is dropped from a height .If it takes0.200 second to cross the last 6.00 m before hitting the ground ,find the height from which it was dropped .
Ans) We need to find HUsing second eqn of motion:6=0.2u-5(0.04).............................u is velocity at h=6mu=31m/sConserving energy:mgh=0.5m(31)2.......................................Datum line for P.E is at 6 m from ground. h= H-6=>h=48.05m=>H=54.05m.
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EXPLANE PLZZ
Q. Why we need additives explain? Additives are the materials added in small quantities to the moulding sand in order to enhance its exiting properties and to impart to it spec
we consider a ball it is dipped from a height equal to square of the intiial distance by 2 multiplide with g(9.8), i.e ans is 1.83 metres.
we consider a ball it is dipped from a height equal to square of the intiial distance by 2 multiplide with g(9.8),
i.e ans is 1.83 metres.
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