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Prove the equations A + A‾ .B + A.B‾ = A + B using the Boolean algebraic theorems ?
Ans. The equation is A + A‾.B + A.B‾ = A + BL.H.S. = A + A‾ .B + A.B‾= (A + A.B‾) + A‾.B= A (1+ B‾) + A‾.B= A + A‾ .B (? 1+B‾ =1)= (A +A‾ ) (A + B)= (A + B) (? A + A‾ = 1)= R.H.SThus Proved
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Subtraction 11001-10110 using 1's complement Ans. 11001 - 10110 01001 is 1' s Compliment of 10110, so 1 1 0 0 1 + 0 1 0 0 1 ------------------ 1 0 0 0 1 0 Add 1
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