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In the given figure, ∠AEF=∠AFE and E is the mid-point of CA. Prove that BD/CD = BF/CE
Ans: Draw CG ¦DF In ΔBDF
CG ¦ DF
∴ BD/CD = BF/GF .............(1) BPT
In ΔAFE
∠AEF=∠AFE
⇒AF=AE
⇒AF=AE=CE..............(2)
In ΔACG
E is the mid point of AC
⇒ FG = AF
∴ From (1) & (2)
BD/CD = BF/CE
Hence proved
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