Initial condition for differential equations, Mathematics

Assignment Help:

Initial Condition(s) are a set of conditions, or a condition on the solution which will permit us to find out that solution which we are after.  Initial conditions are frequently abbreviated of the form:

y(t0) = y0 and or y(k)(t0) = yk

Thus, we can say, initial conditions are values of the solution or/and its derivative(s) at exact points. As we will notice eventually, solutions to "nice sufficient" differential equations are unique and thus only one solution will meet the specified conditions.

For a specified differential equation the number of initial conditions are needed, will depend on the order of the differential equation as we will notice.


Related Discussions:- Initial condition for differential equations

Find the discount factors and linear interpolation, Question: All rates...

Question: All rates should be calculated to 3 decimal places in % (e.g. 1.234%), the discount factors to 5 decimal places (e.g. 0.98765), and the bond prices to 3 decimal place

Explain equivalent fractions, Explain Equivalent Fractions ? Two fracti...

Explain Equivalent Fractions ? Two fractions can look different and still be equal. Different fractions that represent the same amount are called equivalent fractions. Ar

Maths, f all the permutations of the letters of the word chalk are written ...

f all the permutations of the letters of the word chalk are written in a dictionary the rank of this word will be?

find an explicit formula, (a) The generating function G(z) for a sequence ...

(a) The generating function G(z) for a sequence g n is given by G(z) = 1 - 2z/(1 + 3z)3 Give an explicit formula for g n . (b) For the sequence gn in the previous part co

Solve the linear programming problem using simple method, Solve the followi...

Solve the following Linear Programming Problem using Simple method. Maximize Z= 3x 1 + 2X 2 Subject to the constraints:                  X 1 + X 2 ≤ 4

Determine an actual explicit solution, Determine an actual explicit solutio...

Determine an actual explicit solution to y′ = t/y; y(2) = -1. Solution : We already identify by the previous illustration that an implicit solution to this IVP is y 2 = t 2 -

Decision trees illustration, A company is considering whether to enter a ve...

A company is considering whether to enter a very competitive market. In case company decided to enter in market this must either install a new forging process or pay overtime wages

Assemble the coefficient matrix and solve the linear system, Solve discrete...

Solve discrete harmonic mapping of a given surface patch (suppose the surface is genus-0 and with one boundary) 1. Map the boundary loop onto a unit rectangle using chord-length

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd