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Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at the centre.
Since Δ ADF ≅ Δ DFC
∠ADF = ∠CDF
∴ ∠ADC = 2 ∠CDF
Similarly we can prove ∠CEB = 2∠CEF
Since || m
∠ADC + ∠CEB = 180o
⇒2∠CDF + 2∠CEF = 180o
⇒ ∠CDF + ∠CEF = 90o
In Δ DFE
∠DFE = 90o
Calculate the value of the following limit. Solution: This first time through we will employ only the properties above to calculate the limit. Firstly we will employ prop
It is not the first time that we've looked this topic. We also considered linear independence and linear dependence back while we were looking at second order differential equation
Inverse Sine : Let's begin with inverse sine. Following is the definition of the inverse sine. y = sin -1 x ⇔ sin y = x for - ?/2 ≤ y ≤ ?/2 Hen
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