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Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at the centre.
Since Δ ADF ≅ Δ DFC
∠ADF = ∠CDF
∴ ∠ADC = 2 ∠CDF
Similarly we can prove ∠CEB = 2∠CEF
Since || m
∠ADC + ∠CEB = 180o
⇒2∠CDF + 2∠CEF = 180o
⇒ ∠CDF + ∠CEF = 90o
In Δ DFE
∠DFE = 90o
Town x and town y were 270km apart. a car started from town x towards town y at a uniform speed of 60km/hr, while a motorcycle started from town y to town x at a uniform speed of 9
Explain Congruum?
Model of 180 meter tall building using a scale of 1.5 centimeters = 3.5 meters. How tall will the model be?
how do you do hard math!!!
pls help me solve this step by step 6*11(7+3)/5-(6-4)
find the equation of locus of point which lies on bisectors of angles between the coordinate axes
Assume that i) Determine all the roots of f(x) = 0. ii) Determine the value of k that makes h continuous at x = 3. iii) Using the value of k found in (ii), sh
Multiply the given below and write the answer in standard form. (2 - √-100 )(1 + √-36 ) Solution If we have to multiply this out in its present form we would get, (2 -
Logarithmic form and exponential form ; We'll begin with b = 0 , b ≠ 1. Then we have y= log b x is equivalent to x= b y The first one is called
A=30, B=45, b=4
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