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Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at the centre.
Since Δ ADF ≅ Δ DFC
∠ADF = ∠CDF
∴ ∠ADC = 2 ∠CDF
Similarly we can prove ∠CEB = 2∠CEF
Since || m
∠ADC + ∠CEB = 180o
⇒2∠CDF + 2∠CEF = 180o
⇒ ∠CDF + ∠CEF = 90o
In Δ DFE
∠DFE = 90o
x2+y2 r=12
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a)Solve for ?, if tan5? = 1. Ans: Tan 5? = 1 ⇒ ? =45/5 ⇒ ?=9 o . b)Solve for ? if S i n ?/1 + C os ? + 1 + C os ?/ S i n ? = 4 . Ans: S i n ?/1 +
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