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Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at the centre.
Since Δ ADF ≅ Δ DFC
∠ADF = ∠CDF
∴ ∠ADC = 2 ∠CDF
Similarly we can prove ∠CEB = 2∠CEF
Since || m
∠ADC + ∠CEB = 180o
⇒2∠CDF + 2∠CEF = 180o
⇒ ∠CDF + ∠CEF = 90o
In Δ DFE
∠DFE = 90o
compare: 643,251: 633,512: 633,893. The answer is 633,512.
a math problem that involves the numbers $112 for 8 hours
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a company of 10000 shares of rs 100 each declares a annual dividend of 5 %.what is the total amount dividend paid by the company
How do I solve step by step 7
(x^2+x+3)^4
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the mean and standarddeviation of set a is -x ans s respectively.find the mean and standard deviation of set b
(6x+9y) + (11x+13y)
More Optimization Problems Example A window is being built in which the bottom is rectangle and the top is a semicircle. If there framing materials is 12 meters what have
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