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public class TreeTest{ public static void main(String args[]) { Tree t = new Tree(); System.out.println("Populating"); t.insertItem(1); t.insertItem(2); t.insertItem(3); t.insertItem(4); t.insertItem(5); t.insertItem(6); printBreak(t); System.out.println("Balancing"); t.balance(); printBreak(t); System.out.println("Deleting 3"); t.deleteItem(3); printBreak(t); System.out.println("Balancing"); t.balance(); printBreak(t); System.out.println("Populating"); t.insertItem(12); t.insertItem(9); t.insertItem(13); t.insertItem(10); t.insertItem(11); t.insertItem(9); printBreak(t); System.out.println("Balancing"); t.balance(); printBreak(t); System.out.println("Deleting 11, 2, 10"); t.deleteItem(11); t.deleteItem(2); t.deleteItem(10); printBreak(t); System.out.println("Balancing"); t.balance(); printBreak(t); System.out.print("Getting 13's node: "); TreeNode node = t.search(13); System.out.println(node.getData()); System.out.printf("Tree currently has %d nodes\n", t.count()); System.out.print("Looking for 10: "); if(t.findItem(10)) { System.out.println("Found"); } else { System.out.println("Not Found"); } System.out.print("Looking for 9: "); if(t.findItem(9)) { System.out.println("Found"); } else { System.out.println("Not Found"); } System.out.print("In Order: "); t.printInOrder(); System.out.print("Pre Order: "); t.printPreOrder(); System.out.print("Post Order: "); t.printPostOrder(); } public static void printBreak(Tree t) { t.printTree(); System.out.println("--------------------------------"); }}
I can''t figure out how to do this question: "Given two linear equations: ax + by + c = 0 and dx + ey + f = 0" solve for x and y. A, b, c, d, e, and f being inputted from the user.
Write a java code to explain Else If ? if statements are not limited to two cases. You can merge an else and an if to form an else if and test a overall range of mutually exclu
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What is numeric promotion ?
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