Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Program is to define a class as student:
Program is to define a class as student and display the records specific depending upon the number
class student
{
private:
int roll,i;
char name[20],grade;
float per;
int marks[5],total;
int calculate()
per=total/5;
return per;
}
public:
student()// constructor assigning initial values
total=0;
void input();
void disp();
// void disp_spe();
};
void student::input()
cout<<" enter your name "< gets(name); cout<<" enter your roll no. "< cin>>roll; cout<<" enter the marks of five subjects "< for (i=0;i<=4;i++) { cin>>marks[i]; total=total+marks[i]; } } void student::disp() { clrscr(); cout<<" R E P O R T C A R D "<<"\n\n"; cout<<" The name is : "< cout<<" The marks of all subjects is :"<<"\n"; for (i=0;i<=4;i++) { cout< } calculate(); cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
gets(name);
cout<<" enter your roll no. "< cin>>roll; cout<<" enter the marks of five subjects "< for (i=0;i<=4;i++) { cin>>marks[i]; total=total+marks[i]; } } void student::disp() { clrscr(); cout<<" R E P O R T C A R D "<<"\n\n"; cout<<" The name is : "< cout<<" The marks of all subjects is :"<<"\n"; for (i=0;i<=4;i++) { cout< } calculate(); cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
cin>>roll;
cout<<" enter the marks of five subjects "< for (i=0;i<=4;i++) { cin>>marks[i]; total=total+marks[i]; } } void student::disp() { clrscr(); cout<<" R E P O R T C A R D "<<"\n\n"; cout<<" The name is : "< cout<<" The marks of all subjects is :"<<"\n"; for (i=0;i<=4;i++) { cout< } calculate(); cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
for (i=0;i<=4;i++)
cin>>marks[i];
total=total+marks[i];
void student::disp()
clrscr();
cout<<" R E P O R T C A R D "<<"\n\n";
cout<<" The name is : "< cout<<" The marks of all subjects is :"<<"\n"; for (i=0;i<=4;i++) { cout< } calculate(); cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
cout<<" The marks of all subjects is :"<<"\n";
cout< } calculate(); cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
calculate();
cout<<" The percentage is :"< if(per>=85) cout<<" The grade is : A"; else if(per>40) cout<<" the grade is : D"; else cout<<" The grade is : B"; } void student::disp_spe() { int rollno; cout<<" enter the students roll no. you want report card " cin>>rollno; if( void main() { clrscr(); student *data; data=new student; data->input(); data->disp(); data->disp_spe(); delete data; }
if(per>=85)
cout<<" The grade is : A";
else if(per>40)
cout<<" the grade is : D";
else
cout<<" The grade is : B";
void student::disp_spe()
int rollno;
cout<<" enter the students roll no. you want report card "
cin>>rollno;
if(
void main()
student *data;
data=new student;
data->input();
data->disp();
data->disp_spe();
delete data;
In this assignment, you will develop a program named "match" to be used by a dating service to form couples. Given the number of gentlemen, the number of ladies, and a list of acce
Reference Types The symbol "&" is interpreted as an address operator as well as AND operator. This operator is also used to declare a "reference variable". A reference is refer
Suppose that three integer variables intA, intB, and intC have already been defined at the beginning of the main function, write a single C++ statement to read three integers from
construct a console programme for a bank ATM machine.
A: BinarySearchTree.h ---------------------- #ifndef BINARY_SEARCH_TREE_H_ #define BINARY_SEARCH_TREE_H_ #include "dsexceptions.h" #include // For NULL // Binary
A: this is a procedure during exception handling while the destructor is called for all local objects in the stack among the place where the exception was thrown & where this is ca
Scope Rules and Storage Classes The storage class verifies the life of a variable in terms of its duration or its scope. There are four storage classes : automatic static
Structures A structure is a user-defined data type, which may have different data types as its members. Creating a structure is a two-part process. First, a structure template
How do I allocate multidimensional arrays by new? A: There are several ways to do this, based on how flexible you wish the array sizing to be. On one acute, if you know all the
Goals For this assignment you will write programs in C and LC-3 assembly code. Both programs will perform the identical recursive algorithm. The goals of this programming assignmen
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd