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Binary Search Algorithm is given as follows
1. if (low > high)
2. return (-1)
3. mid = (low +high)/2;
4. if ( X = = a [mid])
5. return (mid);
6. if ( X < a [mid])
7. search for X in a (low) to [mid -1];
8. else
9. search for X in a [mid + 1] to a [high];
Q. What do you mean by the best case complexity of quick sort and outline why it is so. How would its worst case behaviour arise?
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