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Preorder traversal of a binary tree
struct NODE
{
struct NODE *left;
int value; /* can take any data type */
struct NODE *right;
};
preorder(struct NODE *curr)
printf("%d", curr->value);
if(curr->left != NULL) preorder(curr->left);
if(curr->right != NULL) preorder(curr->right);
}
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for(int i = 0; i for (int j = n - 1; j >= i ; j--){ System.out.println(i+ " " + j);
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The complexity of searching an element from a set of n elements using Binary search algorithm is O(log n)
Write a program for reversing the Linked list
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