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The emf of the driver cell of a potentiometer is 2V & its internal resistance is negligible . The length of the potentiometer wire is 100cm & resistance is 5 ohm.How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05V/cm? Solution) Potential gradient K= 0.05 V/cm = 5V/mDriver cell emf E=2VResistance of potentiometer wire R1= 5Ω/mSeries resistance, Rs= ?Now, to have K=5V/m, current flowing through the wire must be 1 Ampere ( since current I= 5V/5Ω=1A)So, for the driver cell of emf 2V to generate 1A of current, series resistance ro be connected is 2Ω( since Rs= E/I=2/1=2Ω)Therefore, Rs=2Ω
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