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Network throughput
It is an indicative measure of the point carrying capacity of a network. It is distinct as the total number of messages the network can transmit per unit time. To approximate the throughput, the capacity of the network and the messages number of really carried by the network are calculated. Essentially the throughput is only a fraction of its capacity.
In interconnection network the traffic flow among nodes may be nonuniform and it may be feasible that a certain pair of nodes handles a disproportionately huge amount of traffic. These are called "hot spot." The hot spot can act as a bottleneck and can decrease the performance of the entire network.
An object model for university system Establishing relationship among various classes in the system is the primary activity. Here, we have a simple model of a University System
Describe the VON NEUMANN ARCHITECTURE Most of present computer designs are based on idea developed by John vonNeumann referred to as the VON NEUMANN ARCHITECTURE. V
What is Double entry - Verification In this approach, data is entered twice (using two different people); data is only accepted if both versions match up. Generally used to ve
ascii code add=2unit,replace=1unit,delete=3unit.convert ascii code in minimum cost
Define the PUBLIC and EXTRN directives- Assembler directives PUBLIC and EXTRN directives are very significant to modular programming. PUBLIC used to declare that labels of data
duality
Q. How to Apply Color and Style? 1. In first text description layout cell, select heading text from the word "Fly" through the word "Mountains." 2. In Property inspector,
A palindrome is a string that reads the same from both the ends. Given a string S convert it to a palindrome by doing character replacement. Your task is to convert S to palindrome
Determine the Disadvantages of fact finding - People are usually uncomfortable being watched and may work in a different way - What they are watching may not be represent
Example: CMP AX,BX ; compare instruction: sets flags JE THERE ; if equal then skip the ADD instruction ADD AX, 02 ; add 02
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