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one coin is thrown upword from 100m top building with velocity 15m/s .2s later 2nd coin is dropped downword at what distance from top of building 2nd coin cross first?
Ans) They meet at 11.52 meters from top.(In the question 2nd coin initial velocity is not given. I taken initial velocity as zero).
Because force=dp/dt and force=0 in first law of motion => dp/dt=0 => p=const. or linear momentum is conserved.
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