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MLIL: Unsigned Multiplication Byte or Word: This instruction multiplies an unsigned byte or word by the contents of the AL. The unsigned byte or word can be in any one of the general-purpose registers / memory locations. Most significant word of the result is stored in the resister DX, whereas the least significant word of the result is stored in the resister AX. All the flags are modified depending on the result. The example of the instructions is as shown. Immediate operand is not permitted in this instruction. If the most significant byte or word of the result is the '0' CF and OF both will be set.
Example :
#question.flow chart for a program to find out the number of even and odd numbers from a given series of 16-bit hexadecimal numbers.
PC Bus and Interrupt System The PC Bus utilized a bus controller, address latches, and data transceivers (bidirectional data buffers). 1) Bus controller : ( Intel 8288 Bus
NEG: Negate:- The negate instruction forms the 2's complement of the particular destination in the instruction. For obtaining 2's complement, it subtracts the contents of destinat
REP : Repeat Instruction Prefix :- This instruction is utilized as a prefix to other instructions. The instruction in which the REP prefix is provided, is executed repetitively
write shell to calculate basic salary from given .
#Write a function to calculate the following arithmetic operation and return the result. A = 2 + (3x)3 + y/2n (x, y and n are arguments of the function where x is an integer in the
Write an 8086 program to find out the number of positive numbers and negative numbers from a given series of signed numbers include flow chart ..
Write a program that allows a user to encrypt/decrypt a message using a shift cipher. The user should specify the key and the message. Your program should be able to handle messa
Description Write a MIPS program that reads a string from user input, reverse each word (defined as a sequence of English alphabetic letters or numeric digits without any punctu
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
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