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MLIL: Unsigned Multiplication Byte or Word: This instruction multiplies an unsigned byte or word by the contents of the AL. The unsigned byte or word can be in any one of the general-purpose registers / memory locations. Most significant word of the result is stored in the resister DX, whereas the least significant word of the result is stored in the resister AX. All the flags are modified depending on the result. The example of the instructions is as shown. Immediate operand is not permitted in this instruction. If the most significant byte or word of the result is the '0' CF and OF both will be set.
Example :
1. Write a program that will generate an array of ten random 32-bit integers, and that will display on the monitor the numbers followed by either the words " has the fourth bit se
AAM: ASCII Adjust for Multiplication after execution. This instruction converts the product available in the AL into unpacked BCD format. This follows a multiplication instruct
i want to develop traffic light system so which kind of software is needed to develop this project?
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
Interrupt Priority Management The interrupt priority management logic indicated in given figure can be implemented in several ways. It does not required to be present in system
PLEASE MAY YOU ASSIST ME WITH SAMPLE CODES FOR PROGRAMING A FIRE ALARM MINI PROJECT
write a program that calculates the fibonacci series: except for the first two numbers in the sequence
Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add
String Manipulation Instruction A series of words or data bytes are available in memory at consecutive locations, to be mention to individually or collectively, are known as by
Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH. Solution : For writing this program, we will use
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