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A mol 4:1 mixture of He and CH4 is contained in vessel at 20 bar pressure.Due to a hole in the vessel the gas mixture leaks out.the composition of the mixture,effusing out initially is about.Ans) we know by grahams law of effusion thatrate of effusion(r) is propotional to 1/(density)^1/2hence rate(r)=k/(d)^1/2r=k/(M/2)^1/2 = k.(2/M)^1/2..........................since 2.vapour density(d)=molecular mass(M)hence ratio of compostion during effusion=r1/r2=[ (2/M1) / (2/M2) ] ^1/2r1/r2= (M2/M1)r1/r2=(1.16/4.4)^1/2r1/r2=1compostion of the mixture leaking is equal in propotion.
Interactive periodic table In this interactive periodic table animation you can view details of all components through clicking on it. You can select the colored through option
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