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Level Curves or Contour Curves
Another topic that we should look at is that of level curves or also known as contour curves. The level curves of the function z = f (x, y) are two dimensional curves we acquire by setting z = k , where k is any number. Thus the equations of the level curves are f (x, y) = k .
Notice: occasionally the equation will be in the form f (x, y, z) = 0 and in these cases the equations of the level curves are f (x, y, k) = 0.
You have probably seen level curves (or contour curves, doesn't matter whatever you want to call them) before. If you have ever observed the elevation map for a piece of land, this is not anything more than the contour curves for the function that provides the elevation of the land in that area. Actually, we probably do not have the function which gives the elevation, although we can at least graph the contour curves.
1. Using suffix trees, give an algorithm to find a longest common substring shared among three input strings: s 1 of length n 1 , s 2 of length n 2 and s 3 of length n 3 .
Mike, Dan, Ed, and Sy played together on a baseball team. Mike's batting average was 0.349, Dan's was 0.2, Ed's was 0.35, and Sy's was 0.299. Who had the highest batting average?
All differential equations will doesn't have solutions thus it's useful to identify ahead of time if there is a solution or not. Why waste our time trying to get something that doe
The Central Limit Theorem The theories was introduced by De Moivre and according to it; if we choose a large number of simple random samples, says from any population and find
4.2^2x+1 - 9.2^x + 1=0
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1) A survey was done where a random sample of people 18 and over were asked if they preferred comedies, dramas, or neither. The information gathered was broken down by age group an
find a30 given that the first few terms of an arithmetic sequence are given by 6,12,18...
what is infinite? ..
Pepsi: A dummy variable where 1 denotes choice of Pepsi by the i-th customer and 0 otherwise Price_P: The price of a 2-liter bottle of Pepsi at the time
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