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LC Filter
To the load resistance RL the ripple factor is directly proportional in the inductor filter and inversely proportional to RL in the capacitor filter. Hence if these two filters are joint as LC filter or L section filter as displayed in figure the ripple factor will be independent of RL.
It will increase the time of conduction if the value of inductance is increased. At some vital value of inductance, one diode, either D1 or D2 will all the time conducting.
The output voltage can be expressed like below from Fourier series,
V0 = (2Vm / π) - 4Vm / 3 π cos2 ∞ t
Then the dc output voltage,
Vdc = 2Vm/ π
∴ Vr rms = Irms . Xc = √2 /3. Vdc. Xc /XL
The ripple factor
ϒ= Vr rms / Vdc = √2 /3. Xc /XL
= √2 /3. 1/4 ∞2 CL
∴ Xc = 1 /2 ∞ C & XL 2 ∞ L
Q. A 230-V, single-phase, 60-Hz source supplies two loads in parallel. One draws 10 kVA at a lagging power factor of 0.80 and the other draws 6 kWat a lagging power factor of 0.90.
I would send the project file so you can take a look at it.
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