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Q. JFET Common Source Amplifier?
The common source configuration for a FET is similar to the common emitter bipolar transistor configuration, and is shown in figure. The common source amplifier can provide both a voltage and current gain. Since the input resistance looking into the gate is extremely large the current gain available from the FET amplifier can be quite large, but the voltage gain is generally inferior to that available from a bipolar device. Thus FET amplifiers are most useful with high output-impedance signal sources where a large current gain is the primary requirement. The source by-pass capacitor provides a low impedance path to ground for high frequency components of and hence AC signals will not cause a swing in the bias voltage.
Since the FET gate current is small we can make the approximations is = io and vs = - vas the source is positive with respect to the gate for reverse-bias. Since at low frequencies we can ignore the capacitor the source voltage is given by
Using the transconductance equation we can write
A synchronous generator has a rotor with six poles and operates at 60 Hz. (a) Determine the speed of prime mover of the generator. (b) Repeat part (a) if the generator has 12
Common channel signalling Signalling systems link the variety of switching systems, transmission systems and subscriber equipments in telecommunication network to enable
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Give the examples of sinusoidal with two equations?
HOW CAN I MAKE THIS PROJECT?
In this Project you will simulate a Security Alarm system using the Quick flash board. A switch is placed as shown in the figure below. The main goal of this project is: Task 1:
Q. A two-pole, three-phase synchronous generator has a balanced three-phase winding with 15 turns per phase. If the three-phase currents are given by i a = 100 cos 377t, i b =
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Although the low side is not as good a choice as the high-side local oscillator frequency, let an AM broadcast receiver be designed with a low-side local oscillator. As fc is varie
Q. Let a(t) = [1 + m A x(t)] and x(t) = cos 2πf m t, f m c , and x c (t) = A(t) cos 2πfct . (a) With m A =1, sketch one full period of the AM wave and draw the envelope by co
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