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Q. JFET Common Source Amplifier?
The common source configuration for a FET is similar to the common emitter bipolar transistor configuration, and is shown in figure. The common source amplifier can provide both a voltage and current gain. Since the input resistance looking into the gate is extremely large the current gain available from the FET amplifier can be quite large, but the voltage gain is generally inferior to that available from a bipolar device. Thus FET amplifiers are most useful with high output-impedance signal sources where a large current gain is the primary requirement. The source by-pass capacitor provides a low impedance path to ground for high frequency components of and hence AC signals will not cause a swing in the bias voltage.
Since the FET gate current is small we can make the approximations is = io and vs = - vas the source is positive with respect to the gate for reverse-bias. Since at low frequencies we can ignore the capacitor the source voltage is given by
Using the transconductance equation we can write
2. A 6 pole lap-wound armature having 720 conductors, rotates in a field of 20.35 mWb. (a) If the induced current is 72 A, what is the torque developed by armature? (b) If the indu
Consider the circuit of Figure (a) and obtain the complete solution for the voltage v C (t) across the 5-F capacitor and the voltage v x (t) across the 5- resistor.
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Q. Introduction to power systems? Thomas A. Edison's work in 1878 on the electric light led to the concept of a centrally located power station with distributed electric power
Find the current flow through resistor 12 Ω using Thevenin's Theorem.
Sign flag Since D 7 bit in the results is 0sign flag is reset. This also shown that the results is positive.
What are the predefined interrupts in 8086? The predefined interrupts are, DIVISION BY ZERO (type 0) Interrupt. SINGLE STEP (type 1) Interrupt. NONMASKABLE (ty
A Capacitor-Fed, Voltage-Step-Down, Single-Phase, Non-Isolated Rectifier
Get the equivalent inductance at terminal in circuit: Acquire the equivalent inductance at terminal AB in circuit shown in Figure. Solution Inductances also follow the
draw alogic diagramto implement F=ABCDE using only 3 inputAND gates
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