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writing sin3a.cos3a = sin3a.cos2a.cosa= sin3a.(1-sin2a).cosaput sin a as then cos a da = dt integral(t3(1-t2).dt= integral of t3- t5 dt= t4/4-t6/6 + c where t = sina
Chain Rule : Assume that we have two functions f(x) & g(x) and they both are differentiable. 1. If we define F ( x ) = ( f o g ) ( x ) then the derivative of F(x) is,
Any point on parabola, (k 2 ,k) Perpendicular distance formula: D=(k-k 2 -1)/2 1/2 Differentiating and putting =0 1-2k=0 k=1/2 Therefore the point is (1/4, 1/2) D=3/(32 1/2
7 divided by 66.5
Ask question I have 2 problems I need them after 7 hours
If α,β are the zeros of a Quadratic polynomial such that α + β = 24, α - β = 8. Find a Quadratic polynomial having α and β as its zeros.
HOW WE CAN FACTORISE 12X+7X+1
Parametric Curve - Parametric Equations & Polar Coordinates Here now, let us take a look at just how we could probably get two tangents lines at a point. This was surely not
if each tile with aside that measures one foot, how many tiles will be needed?
1x1
Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve
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