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Prove that the parallelogram circumscribing a circle is rhombus. Ans Given : ABCD is a parallelogram circumscribing a circle. To prove : - ABCD is a rhombus or AB
Method of cylinders or method of shells The formula for the area in all of the cases will be, A = 2 ∏ ( radius ) (heig
81-3/4
In a two dimensional case, the form of the linear function can be obtained if we know the co-ordinates of two points on the straight line. Suppose x' and x" are two
1/cos(x-a)cos(x-b)
es-335
in a garden 1/8 of the flowers are tulips. 1/4 of the tulips are rd. what fraction of the flowers in the garden are red tulips
how do i write a conjecture about the sum of two negative integers.
how to find the indicated term?
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