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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
Two tangents TP and TQ are drawn to a circle with center O from an external point T.prove that angle PTQ=angle 2 OPQ
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Simplify the Boolean function: F (w,x,y,z) = ∑ (0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) (8) Ans: f(w, x, y, z) = ∑(0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) The above
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