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How many lines of address bus must be used to access 2048 bytes of memory when available RAM chips 128 × 8. How many lines of these will be common to each chip?
Ans. AS chips available here of 128 x 8 in size. Thuis means that total 128(27) locations are here and all locations can store 8 bits. Hence the total number of address lines required to access128 locations is 7. Since seven address lines can address 27 locations so all seven lines are common to all chips.
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justify whether the control signal passes through same bus as data ,address and instruction or not?
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