A microprocessor uses RAM chips of 1024 × 1 capacity.

(i) How many chips will be required and how many address lines will be connected to provide capacity of 1024 bytes.
(ii) How many chips will be required to obtain a memory of capacity of 16 K bytes.

Ans. (i) As given available chips = 1024 x 1 capacity and
Required capacity = 1024 x 8 capacity
Number of Chips=  (1024X8)/(1024X1) = 8
Number of address lines are needed = 10 (that is 1024 = 2¹⁰)
Here the word capacity is similar ( 1024 ) so similar address lines will be connected to all chips.

 (ii) Number Of Chips Required = (16X1024X8)/(1024X1) = 128