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A microprocessor uses RAM chips of 1024 × 1 capacity.(i) How many chips will be required and how many address lines will be connected to provide capacity of 1024 bytes.(ii) How many chips will be required to obtain a memory of capacity of 16 K bytes.Ans. (i) As given available chips = 1024 x 1 capacity andRequired capacity = 1024 x 8 capacityNumber of Chips= (1024X8)/(1024X1) = 8Number of address lines are needed = 10 (that is 1024 = 210)Here the word capacity is similar ( 1024 ) so similar address lines will be connected to all chips. (ii) Number Of Chips Required = (16X1024X8)/(1024X1) = 128
Http Hyper Text Transfer Protocol: The WWW protocol that performs the request and regain functions of a server. Generally seen as the first part of a website address. It is t
Q. Develop a menu driven program to implement the logic of the following gates. I. AND Gate II. OR Gate III. NOT Gate IV. Exit The user has option to give n number
A very useful application of assembly is to generate delay loops. These loops are used for waiting for some time before execution of subsequent instruction. However how to find
MS Access provides a vast range of functions some of them are ? It is used by small business, departments of large corporations, and by amateurs to make applications on their d
What are the factors determine the control signals? Contents of the control step counter Contents of the instruction register Contents of the condition code flag
What is cobol codin for heap sort?
Q. What do you mean by Segment numbers? There is a good reason for not leaving determination of segment numbers up to assembler. It permits programs written in 8086 assembly
Distinguish between min terms and max terms. Ans Differentiate between Minterms and Maxterms: a. Each single term in standard Sum Of Products (SOP) form is termed as minterm
Bubbling the Pipeline: Bubbling the pipeline (also known as a pipeline break or pipeline stall) is a technique for preventing, structural, data and branch hazards from taking p
Address phase: A PCI bus transaction starts having an address phase. The initiator, after seeing that it has GNT# and the bus is inactive, drives the target address onto the
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