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A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s The man holding it, can exert . a maximum force of 144 N on the gun. How many bullets can he fire per second at the most? Solution) According to newtons 2nd law..... F=m(v-u)/t144=0.04*n*1200/1 (per second...so t=1s)n=3 bullets / sec
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A block is placed under the head of the claw hammer to aid in removing the nail. The pull on the handle is P39 N, the angle of the hammer to the vertical is P40 and the length of
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He force exerted by machine gun on man''''s hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum =(40/1000*)1200= 48 N .The force exerted by man on machine gun = 144 NTherefore, number of bullets fired = 3
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