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A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s The man holding it, can exert . a maximum force of 144 N on the gun. How many bullets can he fire per second at the most? Solution) According to newtons 2nd law..... F=m(v-u)/t144=0.04*n*1200/1 (per second...so t=1s)n=3 bullets / sec
Is this wavelength in vacuum? Answer; as per mass of CPH is constant, and Vc is for an alone CPH, so wavelength should be in vacuum, that there is not any gravity effect. But i
GALLIUM PHOSPIDE: It has band gap of 2.3ev. it can be used for light emitting diodes which can emit green or red light. The red light is obtained with zinc or cadmium oxide dop
A circuit contains of a 10 volt battery connected in series with a 4 ohm resistor and a 6 ohm resistor. A person computes the current through the 4 ohm resistor using Ohm's Law by
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Quantum theory of gravity
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A certain machine exerts a force of 200 Newton on a box whose masses 30 kilograms. The machine moves the box a distance of 20 meters with a horizontal floor. What amount o
He force exerted by machine gun on man''''s hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum =(40/1000*)1200= 48 N .The force exerted by man on machine gun = 144 NTherefore, number of bullets fired = 3
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