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How many address bits are required to represent 4K memory ?
Ans. 12 address bits are required for representing 4K memory, as4K = 22 x 210 = 212
Therefore 1K = 1024 = 210
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Which of the memories stores the most number of bits ? Ans. most number of bits stores in 32M x 8 As 2 5 x 2 20 = 2 25 Therefore 1M = 2 20 = 1K x 1K = 2 10 x 2 10
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