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How many address bits are required to represent 4K memory ?
Ans. 12 address bits are required for representing 4K memory, as4K = 22 x 210 = 212
Therefore 1K = 1024 = 210
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Eequivalences rules: This conveys a meaning that is actually much simpler so than you would think on first inspection. Hence we can justify this, by using the following ch
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