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How many address bits are required to represent 4K memory ?
Ans. 12 address bits are required for representing 4K memory, as4K = 22 x 210 = 212
Therefore 1K = 1024 = 210
a luminous jewel game c programming start with t and end with t the output will yes or no
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Normal 0 false false false EN-IN X-NONE X-NONE
(a) Convert the following number to single precision IEEE 754 based on the procedure described in class and in the notes. Express the result in hexadecimal. Show all your work.
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