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Graph f ( x ) = ex and g ( x ) = e- x .
Solution
There actually isn't a lot to this problem other than ensuring that both of these exponentials are graphed somewhere.
These will both show up along with some regularity in later sections and their behavior as x goes to both plus and minus infinity will be needed and from this graph we can clearly see this behavior.
If y 1 (t) and y 2 (t) are two solutions to a linear, homogeneous differential equation thus it is y (t ) = c 1 y 1 (t ) + c 2 y 2 (t ) ........................(3) Remem
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Illustration: Find the solution to the subsequent IVP. ty' + 2y = t 2 - t + 1, y(1) = ½ Solution : Initially divide via the t to find the differential equation in
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