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Graph f ( x ) = ex and g ( x ) = e- x .
Solution
There actually isn't a lot to this problem other than ensuring that both of these exponentials are graphed somewhere.
These will both show up along with some regularity in later sections and their behavior as x goes to both plus and minus infinity will be needed and from this graph we can clearly see this behavior.
The logarithm of the Poisson mixture likelihood (3.10) can be calculated with the following R code: sum(log(outer(x,lambda,dpois) %*% delta)), where delta and lambda are m-ve
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