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Gis Applications
So far, you have learnt how GIS can help utilities to obtain snapshots of the locations of substations, lines and cables in relation to their geographical bearings. It could also help plot the locations of consumers along with respect to their feeding networks (starting with the source and ending with the end-user). Because the data are digitised, the use of GIS makes various interactive applications possible. For example, network inventory data could be stored on a computer-aided GIS (Geographical Information System) and it is an effective way of mapping installations; it is also extremely useful for consumer indexing, asset management and engineering analysis.
GIS applications give the requisite managerial inputs for decision making at several levels in a distribution utility. GIS based distribution management system along with varied access of field personnel to centrally located database would give efficient system management. This, in turn, will shorten the billing cycle time and improve finances of the utility. GIS could help to manage complex network information and coupled along with other business process applications it will facilitate the following:
Tick off the material, which is different from the group (A) Constantan. (B) Manganin. (C) Nichrome. (D) Brass. Ans: Tick off the materi
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Research and recommend a sensor for a real full size conveyor system of approximately 1000mm width to detect objects of varying size passing along it. Discuss the suitability of th
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8085 is a one address microprocessor. In 8085 interrupts are classified by hardware and software interupts.
1) Assume that we are given the continuous-time signal xa (t) = xa1 (t) + xa2 (t) + xa3 (t), where, xa1 (t) = 2 + cos3 (2pf1 t + p 3 ) + 2 cos(2pf2 t), xa2 (t) = 2 cos(2pf3 t)
Working of Hartley oscillator : When the collector supply voltage Vcc is switched on, the capictor gets charged. The capacitor discharges through the inductor, setting up oscil
Q. In a differentiating circuit, R=10 kW,and C=2.2μF.If the input voltage goes from 0V to 10 V at a constant rate in 0.4s, determine the output voltage. Solution: e 0 =
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