If an item costs $1.45 to what amount will louise round, Louise is estimati...

Louise is estimating the cost of the groceries in her cart. She rounds the cost of every item to the nearest dollar to form her calculations. If an item costs $1.45, to what amount

Recursively, Let a 0 , a 1 ::: be the series recursively defined by a 0 =...

Let a 0 , a 1 ::: be the series recursively defined by a 0 = 1, and an = 3 + a n-1 for n ≥ 1. (a) Compute a 1 , a 2 , a 3 and a 4 . (b) Compute a formula for an, n ≥ 0.

Area of a parallelogram x what is the height in terms of x, The area of a p...

The area of a parallelogram is x 8 . If the base is x 4 , what is the height in terms of x? Since the area of a parallelogram is A = base times height, then the area divided by

Find the co ordinates of p such that ap =3/7 ab and p lies, If A & B are (-...

If A & B are (-2,-2) and (2,-4) respectively, find the co ordinates of P such that AP =3/7 AB and P lies on the line segment AB.

Determine the inverse transform, Determine the inverse transform of each of...

Determine the inverse transform of each of the subsequent. (a)    F(s) = (6/s) - (1/(s - 8)) + (4 /(s -3)) (b)   H(s) = (19/(s+2)) - (1/(3s - 5))  + (7/s 2 ) (c)    F(s) =

Minimizing the sum of two distances, The value of y that minimizes the sum ...

The value of y that minimizes the sum of the two distances from (3,5) to (1,y) and from (1,y) to (4,9) can be written as a/b where a and b are coprime positive integers. Find a+b.

Polynomials, write the zeros of underroot3power2 -8x+4underroot 3

write the zeros of underroot3power2 -8x+4underroot 3

Problem solving sentence, a cheeseburger cost $6.39 more than a burger of $...

a cheeseburger cost $6.39 more than a burger of $2.29, what is the difference?

value of integration , what is the value of integration limit n-> infinity...

what is the value of integration limit n-> infinity [n!/n to the power n]to the power 1/n Solution)  limit n-->inf.    [1 + (n!-n^n)/n^n]^1/n = e^ limit n-->inf.    {(n!-n^n)

Arithmetic sequences and series,