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Finding the Equation of a line, Given a Slope and a Point ?
Find the equation of a line with slope m = 2, which passes through the point (-1, -3).
Solution:
Use the point-slope form:
y - y1 = m(x - x1 )
With m = 2 and (x1 ,y1 ) = (-1, -3). Substitute for m, x1 , and y1:
y - ( -3) = 2(x - ( -1)).
Simplify:
y + 3 = 2x + 2
y = 2x - 1.
(This is the slope-intercept form.)
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Example Multiply 3x 5 + 4x 3 + 2x - 1 and x 4 + 2x 2 + 4. The product is given by 3x 5 . (x 4 + 2x 2 + 4) + 4x 3 . (x 4 + 2x 2 + 4) + 2x .
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