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Find the probability of having 53 Sundays in
(i) a leap year (ii) a non leap year (Ans:2/7 , 1/7 )
Ans: An ordinary year has 365 days i.e. 52 weeks and 1 day
This day can be any one of the 7 days of the week.
∴ P(that this day is Sunday) = 1/7
Hence, P(an ordinary year has 53 Sunday) = 1/7
A leap year 366 days i.e. 52 weeks and 2 days
This day can be any one of the 7 days of the week
∴ P (that this day is Sunday) = 2/7
Hence, P(a leap year has 53 Sunday) = 2/7
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