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50ml of 0.1M NH4OH ,25ml NH4Cl weere used to make a buffer . what is the PH is if Pkbis 4.8?Solution) The given buffer is a base buffer[NH4OH] =[(50*0.1)/75][NH4Cl] =[(25*2)/75]From the principle V1M1=V2M2For a base buffer pOH = pKb + log [Salt/Base]thus pOH 4.8+ log [{(25*2)/75}/{(50*0.1)/75}] = 4.8+ log (10) = 4.8+1 =5.8Therefore pH = (14-pOH) = (14-5.8) = 8.2
Differentiate between extrinsic and intrinsic semiconductor. Obtain an expression for the carrier concentration for an intrinsic semi-conductor. Also demonstrate that Fermi level i
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notes on s-block elements
There are two conditionfor foramtion of anions a) High Electron affinity b) Small size Less charge of an atoms form anion more simply
What is the use of bhc
Since flourine is very electronegative as a result hydrogen makes a very positive character.as a result the H-bonding is very strong because of large difference in electronegativit
what is the equivalent weight of Ca in Ca3(PO4)2?
An element has the electronic configuration 1s 2 , 2s 2, 2p 6 , 3s 2 , 3p 2 . Its valency electrons are: (1) 6 (2) 2 (3) 3 (4)4 Ans: 4
ionic bond has low energy
It is important to differentiate the stoichiometric or empirical formula of a molecular substance from its molecular formula. The former expresses only the relative numbers of atom
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