Find the core radius necessary for a single mode operation, Electrical Engineering

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Find the core radius necessary for a single mode operation at 1320nm of a step index fibre with n1=1.48 and n2=1.478. What are the N.A and maximum acceptance angle for this fibre?

Ans:

For a single mode step index fibre, V≤2.405

Take V= 2.4

Given  Λ= 1320nm

             n1=1.48

             n2=1.478

We have        V= Πd (n12- n22)½  / λ                                                            

Substituting the values of V, n1, n2, d and solving for Λ, we get

              d= 1.311 x 10-5 m

Hence, core radius is given by

    r=d/2= 6.555µm

Numerical aperture

                    Sinψ = (n12- n22)½= (1.482- 1.4782)½ =0.076

Maximum acceptance angle,

               ψmax= sin-1(0.076)

                       = 4.411°


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