Q. Illustrate how do you find the refractive index of a liquid by using total internal reflection?

Answer:-

Using Snell's law

n (1) = (n (2) x sin angle (2)) / sin angle (1).

n (1) = The refractive index of the greatly optically dense medium.

n (2) = The refractive index of the fewer optically dense medium.

angle (1) = The critical angle of the two mediums.

angle (2) = 90 degrees ever since when light is at the critical angle it undergoes total internal reflection.s

Since sin 90= 1 this is able to be ignored resulting in n (1) = n (2) / sin angle (1)