external division of section formula, Mathematics

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give me the derivation of external division of sectional formula using vectors

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Prove that abc=60 degree, ABC is a right triangle right-angled at C and AC=...

ABC is a right triangle right-angled at C and AC=√3 BC. Prove that ∠ABC=60 o . Ans:    Tan B = AC/BC Tan B = √3 BC/BC Tan B =√3 ⇒ Tan B = Tan 60 ⇒ B = 60

Solve factors for given equations, 1/a+b+x  =1/a+1/b+1/x    a+b ≠ 0 ...

1/a+b+x  =1/a+1/b+1/x    a+b ≠ 0 Ans: 1/a+b+x  =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒  x - ( a + b + x )/ x ( a + b + x )   = + a + b/ ab ⇒

Find the quadratic polynomial, Find the Quadratic polynomial whose sum and ...

Find the Quadratic polynomial whose sum and product of zeros are √2 + 1, 1/ √2 + 1 Ans:    sum = 2  √2 Product = 1 Q.P = X 2 - (sum) x + Product ∴ x 2 - (2 √2 )

E is irrational, If e were rational, then e = n/m for some positive integer...

If e were rational, then e = n/m for some positive integers m, n. So then 1/e = m/n. But the series expansion for 1/e is 1/e = 1 - 1/1! + 1/2! - 1/3! + ... Call the first n v

Diabetes/Calcuation, #sally wieghs 100kg. According to the 50/50 basal bolu...

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Quotient rule (f/g)'' = (f''g - fg'')/g2, Quotient Rule (f/g)' = (f'g - ...

Quotient Rule (f/g)' = (f'g - fg')/g 2 Here, we can do this by using the definition of the derivative or along with Logarithmic Definition. Proof Here we do the pr

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The scores of students taking the ACT college entrance examination are normally distributed with a mean µ = 20.1 and a standard deviation σ = 5.8. a)    A single student is sele

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