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Q. Explain the working of a photo - transistor with a sketch
A second optoelectronic device that conducts current when exposed to light is the PHOTOTRANSISTOR. A phototransistor, however, is much more sensitive to light and produces more output current for a given light intensity that does a photodiode. Figure given below shows one type of phototransistor, which is made by placing a photodiode in the base circuit of an NPN transistor. Light falling on the photodiode changes the base current of the transistor, causing the collector current to be amplified. Phototransistors may also be of the PNP type, with the photodiode placed in the base-collector circuit.
Figure shown below illustrates the schematic symbols for the various types of phototransistors. Phototransistors may be of the two-terminal type, in which the light intensity on the photodiode alone determines the amount of conduction. They may also be of the three-terminal type, which have an added base lead that allows an electrical bias to be applied to the base. The bias allows an optimum transistor conduction level, and thus compensates for ambient (normal room) light intensity.
a 4 bit synchronous counter uses flip flops with propagation delay times of 15ns each. what will be the maximum possible time requires for change of state?
A two-pole, three-phase, 60-Hz, wye-connected, round-rotor synchronous generator has N a = 12 turns per phase in each armature phase winding and flux per pole of 0.8Wb. Find the r
Q. In the non inverting summing amplifier of Figure, let R d = 1k and M = 6. Find R f so that v =
An audiomessage is band-limited to 15 kHz, sampled at twice the Nyquist rate, and encoded by a 12-bit natural binary code that corresponds to Lb = 212 = 4096 levels, all of which s
Q. How numbering plan is achieved in modern telephony? Ans: The purpose of numbering plan is to uniquely identify every subscriber connected to a telecommunication network.
Q. Explain Power semiconductor-controlled drives? Power electronics deals with the applications of solid-state electronics for the control and conversion of electric power. Con
Disadvantages
Q. A BJT is biased by the method shown in Figure. If V BEQ = 0.7V, β = 100, V CEQ = 10 V, and I CQ = 5 mA, find I 1 , I 2 , and IEQ.
Q. A four-pole, lap-wound armature has 144 slots with two coil sides per slot, each coil having two turns. If the flux per pole is 20 mWb and the armature rotates at 720 r/min, cal
a cast steel has minimun diameter of 200 mm and a cross sectional area of 250/1000000 m . calclate the mmf to produce a flux of300/1000000 Wb.
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