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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
i have an array of structs, and am trying to make a pointer that can point to a certain struct within the array
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A: This will turn o_ "name mangling" for func so that one can connect to code compiled by a C compiler.
# include stdio.h> # include string.h> # include conio.h> void main() { int i=0,j=0,b=0,count=0; int a[100]; for(i=0;i
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